…the way I read it kind of suprised me, it still had very high torque at low rpm. Surely the HP number is partially irrelevant as torque is the force that the motor can produce rotating where as HP is more a number calculated from it against an RPM?!
I am afraid you have a totally incorrect understanding of the physical concepts and the process of cutting metal on a lathe. Let me see if I can explain further without being a smarty knickers.
First, let’s look at the cutting process, which is shearing. Think about pulling a knife along the top of a lump of butter with the knife vertical. The knife will shear a layer of butter rather than cut in the sense of pushing the knife vertically into the butter. This is what happens when cutting on a lathe; it is a shearing process not cleaving.
To shear the metal the work needs to be pushed down onto the cutting tool and the force needed to do this is what causes the metal to shear.
Second, let’s revise some basic physics. Power is a calculated unit rather than a base unit, but is nevertheless useful and represents the rate at which work is done with respect to time. The rate at which metal can be removed is determined by the force needed to push the work past the cutting tool, and the velocity at which the work passes the cutting tool. The force is generated by the applied torque. But torque is not a force but is a moment. Torque is the product of length and force. For a constant value of torque the force is dependent upon the radius at which is it measured. Double the distance and the force halves.
The last sentence is the key to understanding the cutting process. Now let’s look at a practical example. Suppose we have a torque of 10Nm across the speed range of the motor. If we turn steel of 20mm diameter (10mm radius) at 1000rpm we will have a force at the cutting tool of 1000N available for shearing metal. The force needed will be determined by the material, the depth of cut and the width of cut, ie, the feedrate per revolution. Now suppose we want to turn steel of 200mm diameter (100mm radius). We need the same surface speed for cutting, so the work rpm will drop to 100rpm. Instead of cutting at a radius of 10mm we are now cutting at a radius of 100mm. The torque remains at 10Nm so the force at the cutting tool will now be 100N, ie, a reduction of ten. So the depth of cut and/or the feedrate will need to be reduced. Consequently less metal will be removed per unit time.
If we want to maintain the metal removal rate across a range of spindle speeds we need constant power at the spindle, not constant torque. Constant power is what is provided by a gear or belt driven spindle. As the speed decreases the torque increases in proportion so the power at the cutting tool stays constant. Thus the rate of metal removal stays constant.
Julie