Posted by SillyOldDuffer on 11/10/2019 11:26:56:
I can do trigonometry on right angled triangles, but ABC isn't right angled.
Draw a right angled triangle with AC as its base, and the other vertex, E on the circumference and A as the right angle.
The line CE is now a diameter, as the hypotenuse of a right angled triangle in a circle is always the diameter.
So from trig AC / CE is sin e
As CE = D and AC =B then, if the formula is correct, sin e = sin b.
Who can do the geometry that proves e= b ?