Forcing a part into “home position”

Forcing a part into “home position”

Home Forums Beginners questions Forcing a part into “home position”

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  • #234103
    Mark Fry
    Participant
      @markfry71618

      Hi all

      I have a design with two parts (at the moment): a fixed 10cm ring with vertical tracks and a freely rotating block with a cut that slides along that tracks:

      I'm trying to find a low profile way to ensure that whenever the cut in the moving block faces upward vertically, the block is pushed up (almost) touching the inner face of the ring. That is, it returns to its "home position" whenever the cut faces up:

      The only way I could think of is to have a part like a leg sticking out from the bottom of the block so that it pushes against the ring or an external track (near the bottom of the ring) whenever the cut nears facing upward. The issue is that this leg will require quite a bit of extra space, e.g., when the cut faces down but the block is at the top, the leg will point upward. The method should not constrain the block's movement along the tracks or rotation.

      Does anyone know of a better way?

      Any thought appreciated.

      Edited By Mark Fry on 11/04/2016 08:33:44

      #8097
      Mark Fry
      Participant
        @markfry71618
        #234106
        John Haine
        Participant
          @johnhaine32865

          What makes the block move? It's very hard to suggest ideas without more information I think.

          #234110
          Mark Fry
          Participant
            @markfry71618

            Posted by John Haine on 11/04/2016 09:00:07:

            What makes the block move? It's very hard to suggest ideas without more information I think.

            Sure. The block is just driven by a crank. Indeed, the crank can freely shift vertically. However, i'm hoping the block (along with the crank) to return to the home position whenever the cut points upwards.

            Thanks

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