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Dividing head problem with angles.

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Corrected Dividing Tables for Vertex HV6 Dividing Head

Corrected Dividing Tables for Vertex HV6 Dividing Head

This is a corrected table giving correct figures for dividing with the vertex HV6 dividing head.

Brian Abbott17/10/2016 12:16:17
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380 forum posts
61 photos

Hello all.

I apologies if this subject has already being covered.

I own a small vertex 6” dividing table ( HV6 I think ) and am looking for a way to be able to use the 3 supplied plates to turn the table a certain angle..

Ie.. how many turns + holes to rotate the table say 33.5° or can I not be that exact ?

Maths is not my strongest subject so ideally a simple solution if there is one..

Thanks in advance.

Brian

D Hanna17/10/2016 13:07:53
42 forum posts
5 photos

1 turn of crank on your Vertex = 4 deg = 240 minutes

33.5 deg = 2010 minutes

Turns of crank = minutes/240 = 2010/240 = 8 3/8

3/8 =6/16

You have a 16 hole plate

8 complete turns of crank+ 6 spaces in 16 hole circle = 33.5 deg exactly

Note: that will be 7 holes between sector arms on your 16 hole plate

 

Hope that helps

Edited By D Hanna on 17/10/2016 13:16:04

SillyOldDuffer17/10/2016 13:11:28
4130 forum posts
832 photos

Not sure if I'm answering the question but this site (search 'HV6' has a link to this table.

I'm too busy at the moment to think about how to calculate angles like 33.5 degrees but I'm sure it's possible provided there's actually an approximation close enough given a particular table and wheels.

If no-one else can provide the answer I'll have a go later.

edit: And D Hanna posted the answer while I was typing!

Dave

Edited By SillyOldDuffer on 17/10/2016 13:13:01

Brian Abbott17/10/2016 22:33:35
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380 forum posts
61 photos

Thanks both for replying, understand now what i need to do.

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